
Home > Just Math
2/5 ≤ m/n ≤ 3/5 (Posted on 2009-10-20) |
|
Five distinct n-digit binary numbers are such that for any two numbers chosen from them the digits will coincide in precisely m places. There is no place with the common digit for all the five numbers. At least one of the binary numbers contains leading zero.
Prove that 2/5 ≤ m/n ≤ 3/5.
No Solution Yet
|
Submitted by K Sengupta
|
Rating: 4.0000 (1 votes)
|
|
Comments: (
You must be logged in to post comments.)
|
 |
Please log in:
Forums (0)
Newest Problems
Random Problem
FAQ |
About This Site
Site Statistics
New Comments (5)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On
Chatterbox:
|