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2/5 ≤ m/n ≤ 3/5 (Posted on 2009-10-20) |
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Five distinct n-digit binary numbers are such that for any two numbers chosen from them the digits will coincide in precisely m places. There is no place with the common digit for all the five numbers. At least one of the binary numbers contains leading zero.
Prove that 2/5 ≤ m/n ≤ 3/5.
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