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Square and Consecutive Cubes (Posted on 2009-12-17) Difficulty: 3 of 5
N is a positive integer such that N2 is expressible as the difference of two consecutive perfect cubes, and 2N + 79 is a perfect square.

Determine the maximum value of N.

No Solution Yet Submitted by K Sengupta    
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Some Thoughts A start! | Comment 1 of 4

Playing in Excel a bit with the cubes of 1 through 10,000, the maximum and only workable value I've found for N (so far) is 181; that is:

105^3 - 104^3 = 1,157,625 - 1,124,864 = 32,761 = 181^2, with 2*181 + 79 = 441 = 21^2.

Not sure whether 181 is necessarily 'the maximum value'.  Would like to explore further beyond 10,000, but the 2010 Winter Olympic Torch has just arrived here in Toronto and the relay's arriving outside my office building for a big ceremony in just a little while.  Can't miss that!! 

 


  Posted by rod hines on 2009-12-17 15:56:55
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