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Double Coverage (Posted on 2009-09-29) Difficulty: 2 of 5
The two pentominos pictured below cannot tile any rectangle.
+--+  +--+   +--+--+
|  |  |  |   |  |  |
+--+--+--+   +--+--+--+--+
|  |  |  |      |  |  |  | 
+--+--+--+      +--+--+--+
Take eight copies of one pentomino and place them on a 4x5 rectangle such that each 1x1 subsquare of the rectangle has exactly two pentominos covering it.

No Solution Yet Submitted by Brian Smith    
Rating: 3.0000 (1 votes)

Comments: ( You must be logged in to post comments.)
  Subject Author Date
Solutionre(2): considering second pentominoCharlie2009-09-30 01:48:37
re: considering second pentominoBrian Smith2009-09-30 00:45:40
considering second pentominoCharlie2009-09-29 13:51:53
computer solution for first pentominoCharlie2009-09-29 13:03:04
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