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Eccentric Integral (Posted on 2010-02-18) Difficulty: 2 of 5
The respective eccentricities of the hyperbola x2/ a2 - y2/ b2 = 1 and its conjugate y2/ b2 - x2/ a2 = 1 are denoted by e and f(e).

Evaluate:

√2
(f(e) + f(f(e))) de
1

See The Solution Submitted by K Sengupta    
Rating: 5.0000 (1 votes)

Comments: ( You must be logged in to post comments.)
  Subject Author Date
analytical solutionDaniel2010-02-19 12:15:26
Some ThoughtsAn attempt using numerical integration (spoiler?)Charlie2010-02-19 11:48:51
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