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Calculus
Eccentric Integral (
Posted on 2010-02-18
)
The respective
eccentricities
of the hyperbola x
2
/ a
2
- y
2
/ b
2
= 1 and its conjugate y
2
/ b
2
- x
2
/ a
2
= 1 are denoted by e and f(e).
Evaluate:
√2
∫
(f(e) + f(f(e))) de
1
See The Solution
Submitted by
K Sengupta
Rating:
5.0000
(1 votes)
Comments: (
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)
Subject
Author
Date
analytical solution
Daniel
2010-02-19 12:15:26
An attempt using numerical integration (spoiler?)
Charlie
2010-02-19 11:48:51
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