Home > Just Math
| Positive Integer Choice (Posted on 2010-04-22) |
 |
Prove that it is possible to choose only up to a set of 100 integers (and no more) from the first 200 positive integers - that is 1, 2,....,200; so that no integer in the set divides any other.
|
No Solution Yet
|
Submitted by K Sengupta
|
|
Rating: 1.0000 (2 votes)
|
|
Comments: (
You must be logged in to post comments.)
| |
Subject |
Author |
Date |
 | Approach | broll | 2010-04-22 15:35:59 |
 | Approach. | Vee-Liem Veefessional | 2010-04-22 13:33:57 |
|
|
Please log in:
Forums (0)
Newest Problems
Random Problem
FAQ |
About This Site
Site Statistics
New Comments (2)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On
Chatterbox:
|
