If the days of the week are represented as follows:
MO TU W TH F SA SU
and are numbered 1 to 7 as follows:
MO TU W TH F SA SU
1 2 3 4 5 6 7
assign to each letter a nonzero digit so that the numbers represented by the day abbreviations given are each divisible by the digit assigned to that day, but by no higher digit.
(In reply to
SPOILER by Ady TZIDON)
I agree with your second solution, but your first one has some problems.
For TU = 78, it is divisible by 2 and 39. 39 is a multiple of 3, meaning that 78 itself is divisible by 3. So, that value, as well as 24 (4x6 = 3x8) don't follow the rules, and thus can't be part of the solution.
So, your first solution is invalid, leaving only the second solution as a possibility.

Posted by Justin
on 20100217 15:01:26 