Ordinal Days (Posted on 2010-02-17)

MO TU W TH F SA SU

and are numbered 1 to 7 as follows:

MO TU  W TH  F SA SU
 1  2  3  4  5  6  7

	Submitted by Charlie
Rating: 2.5000 (2 votes)
Solution:	(Hide)
MO TU W TH F SA SU 89 74 3 76 5 12 14 w = 3: f = 5 used(3) = 1: used(5) = 1 FOR m = 1 TO 9 IF used(m) = 0 THEN used(m) = 1 FOR o = 1 TO 9 IF used(o) = 0 THEN used(o) = 1 mo = m * 10 + o good = 1 FOR i = 2 TO 7 IF mo MOD i = 0 THEN good = 0: EXIT FOR NEXT i IF good THEN FOR t = 1 TO 9 IF used(t) = 0 THEN used(t) = 1 FOR u = 1 TO 9 IF used(u) = 0 THEN used(u) = 1 tu = t * 10 + u good = 1 FOR i = 3 TO 7 IF tu MOD i = 0 THEN good = 0: EXIT FOR NEXT i IF tu MOD 2 = 0 AND good = 1 THEN FOR h = 1 TO 9 IF used(h) = 0 THEN used(h) = 1 th = t * 10 + h good = 1 FOR i = 5 TO 9 IF th MOD i = 0 THEN good = 0: EXIT FOR NEXT i IF th MOD 4 = 0 AND good = 1 THEN FOR s = 1 TO 9 IF used(s) = 0 THEN used(s) = 1 FOR a = 1 TO 9 IF used(a) = 0 THEN used(a) = 1 sa = s * 10 + a good = 1 FOR i = 7 TO 9 IF sa MOD i = 0 THEN good = 0: EXIT FOR NEXT i IF sa MOD 6 = 0 AND good = 1 THEN su = s * 10 + u good = 1 FOR i = 8 TO 9 IF su MOD i = 0 THEN good = 0: EXIT FOR NEXT i IF su MOD 7 = 0 AND good = 1 THEN PRINT mo; tu; w; th; f; sa; su END IF used(a) = 0 END IF used(a) = 0 END IF NEXT used(s) = 0 END IF NEXT END IF used(h) = 0 END IF NEXT END IF used(u) = 0 END IF NEXT used(t) = 0 END IF NEXT END IF used(o) = 0 END IF NEXT used(m) = 0 END IF NEXT Based upon Enigma No. 1575, "All our days", by Adrian Somerfield, New Scientist, 12 December 2009, page 28.

	Subject	Author	Date
	Puzzle Thoughts	K Sengupta	2023-09-22 11:00:25
	Solution	Dej Mar	2010-02-18 03:40:26
	re(2): SPOILER	Ady TZIDON	2010-02-17 15:47:07
	re: SPOILER	Justin	2010-02-17 15:01:26
	SPOILER	Ady TZIDON	2010-02-17 13:49:51