perplexus.info :: Just Math : Reciprocal Equation #3

Reciprocal Equation #3 (Posted on 2010-07-02)

Determine the total number of triplets (x, y, z) of positive integers, with x ≤ y ≤ z, that satisfy this equation:

1/x + 1/y + 1/z = 7/15

Submitted by K Sengupta

Rating: 3.5000 (2 votes)

Solution: (Hide)

(x, y, z)= (3, 8, 120), (3, 9, 45), (3, 10, 30), (3, 12, 20), (3, 15, 15), (4, 5, 60), (4, 6, 20), (5, 5, 15), and: (5, 6, 10) are the required triplets satistying the given conditions.
Therrfore, the required number of triplets is 9.

Comments: ( You must be logged in to post comments.)

Subject	Author	Date
re(2): Solution	brianjn	2010-07-03 10:33:09
re: Solution	broll	2010-07-03 04:22:46
Solution	Dej Mar	2010-07-02 17:03:32
some starters	ed bottemiller	2010-07-02 13:47:56
possible solution	broll	2010-07-02 13:36:23

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