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Product = Sum + 2 (
Posted on 20100914
)
Determine all possible triplet(s) (p, q, r) of positive real numbers, with p ≤ q ≤ r, that satisfy the following system of equations:
p*q + q*r + p*r = 12 , and:
p*q*r = p + q + r + 2
No Solution Yet
Submitted by
K Sengupta
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A negative solution
 Comment 2 of 3 
I know the problem asks for a positive solution, but here's a negative one: (5.5, 1, 1)
p*q + q*r + p*r = 5.5 + 5.5 + 1 = 12
p*q*r = .5.5 = p + q + r + 2
Posted by
Steve Herman
on 20100914 22:44:56
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