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Product = Sum + 2 (Posted on 2010-09-14) Difficulty: 3 of 5
Determine all possible triplet(s) (p, q, r) of positive real numbers, with p ≤ q ≤ r, that satisfy the following system of equations:

p*q + q*r + p*r = 12 , and:
p*q*r = p + q + r + 2

No Solution Yet Submitted by K Sengupta    
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Some Thoughts A negative solution | Comment 2 of 3 |
I know the problem asks for a positive solution, but here's a negative one:   (-5.5, -1, -1)

p*q + q*r + p*r = 5.5 + 5.5 + 1 = 12
p*q*r = -.5.5 = p + q + r + 2





  Posted by Steve Herman on 2010-09-14 22:44:56
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