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18-yes, 17-maybe (Posted on 2010-08-06) Difficulty: 2 of 5
Prove that among any 18 consecutive 3-digit numbers there must be at least one which is divisible by the sum of its digits.

No Solution Yet Submitted by Ady TZIDON    
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Some Thoughts re: a beautiful computer proof | Comment 2 of 4 |
(In reply to computer proof by Charlie)

Beautiful indeed!

Not only you have proven the 18-yes but upgraded 
 the 17-may-be to 17-no by listing all existing
17 numbers strings.

Now- not a big deal- try to solve it analytically.


  Posted by Ady TZIDON on 2010-08-06 16:20:21
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