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Equidistant points on the Axes (Posted on 2003-03-28) Difficulty: 2 of 5
Two points, A and B, are on the Cartesian plane at (-1,4) and (9,6).

A. What point on the x-axis is equidistant from each of these two points?

B. What point on the y-axis is equidistant from these two points?

See The Solution Submitted by Charlie    
Rating: 3.2000 (10 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
re: pretty easy :easier | Comment 6 of 9 |
(In reply to pretty easy by DuCk)

The segment connecting the points has slope = 1/5

The perpendicular bisector of the segement has slope -5 and passes through the point (4,5). Its equation is y=-5x+25
(Recall every point on the perp. bisector is equidistant from the endpoints)

This line has y-int.=25 and x-int=5
  Posted by Jer on 2003-03-28 07:33:59

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