All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Just Math
Nineteen triplets (Posted on 2010-09-23) Difficulty: 3 of 5
19 numbers are written on a circumference of a circle, in any order.
Their sum is 203 and the biggest number is X.
Any 3 adjacent numbers sum up to 31 or more.

What is the maximal possible value of X ?
If this number is selected, what can be said about the other 18?

No Solution Yet Submitted by Ady TZIDON    
Rating: 3.0000 (2 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Largest element | Comment 3 of 10 |
One can separate the 19 elements into a largest one, and then partition the rest into 6 triplets of 3 adjacent numbers.

Each triplet must sum to at least 31, and thus under any configuration, all six triplets must together sum to at least 6*31 or 186, thus the largest element can be at most 203-186 or 17.

Notice none of the other 18 can be larger than 17 by how the largest element was chosen.
  Posted by Gamer on 2010-09-24 02:47:24
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (2)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2017 by Animus Pactum Consulting. All rights reserved. Privacy Information