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Sum Divisors - 1 = Number (Posted on 2010-12-16) Difficulty: 3 of 5
Determine all possible values of a positive integer P, such that P-1 has three divisors Q, R and S, with Q < R < S, such that: Q + R + S = P

No Solution Yet Submitted by K Sengupta    
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Some Thoughts re: Solution | Comment 2 of 3 |
(In reply to Solution by Jer)

Great job, Jer!

You can simplify the case where z = 1:

z=1 means (P-1)/S = 1
Which means P-1 = S
But P = Q + R +S, so this means 1 = Q + R, which is impossible

  Posted by Steve Herman on 2010-12-18 11:26:26
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