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Sum Divisors  1 = Number (
Posted on 20101216
)
Determine all possible values of a positive integer P, such that P1 has three divisors Q, R and S, with Q < R < S, such that: Q + R + S = P
No Solution Yet
Submitted by
K Sengupta
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re: Solution
 Comment 2 of 3 
(In reply to
Solution
by Jer)
Great job, Jer!
You can simplify the case where z = 1:
z=1 means (P1)/S = 1
Which means P1 = S
But P = Q + R +S, so this means 1 = Q + R, which is impossible
Posted by
Steve Herman
on 20101218 11:26:26
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