All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Just Math
Hail to thee, Sofia! (Posted on 2010-12-13) Difficulty: 2 of 5


Let p= 1/2*3/4*5/6*7/8..*99/100.

Is p bigger than, equal to or less than 0.1 ?

The famous Sofia Kovalevskaya (1850-1891) solved this problem allegedly in no time, when she was only twelve years old.

Please provide your answer without programming and without direct evaluation.

No Solution Yet Submitted by Ady TZIDON    
Rating: 3.0000 (1 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Solution re(2): What does not work..FIGURES CAN'T LIE . Comment 10 of 10 |
(In reply to re: What does not work..FIGURES CAN'T LIE . by Ady TZIDON)

Of course it is not admissible to manipulate approximations as I did (there were no infinities involved) since there was no indication of the size of the error terms.  Clearly it didnt work but it was interesting that everything cancelled out so I shared it anyway.

I still want to do it the hard way so here is what I have:

Formula (26) on
http://mathworld.wolfram.com/StirlingsApproximation.html

Gives a way that does work.
Simplified it says a(n) < n! < b(n)
My rewriting of the expression was x = 100!/(2^100(50!)^2)
On the left put the smaller in the numerator and the larger in the denominator.  On the right do the opposite to get.

a(100)/(2^100*b(50)^2) < x < b(100)/(2^100*a(50)^2)

which simplifies (WORK OMITTED) to

e^(-901/360300)/sqrt(50pi) < x < e^(-1799/721200)/sqrt(50pi)

Focus in the right side.   The numerator is clearly less than 1 and the denominator is greater than 10 so
x < 1/10


  Posted by Jer on 2010-12-14 10:39:09

Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (2)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2017 by Animus Pactum Consulting. All rights reserved. Privacy Information