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| Geometric Integers II (Posted on 2011-08-02) |
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Consider three positive integers x, y and z in geometric sequence with x < y < z < 2011 and, x+y=z+1 and determine all possible triplets (x,y,z) that satisfy the given conditions.
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Submitted by K Sengupta
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Rating: 5.0000 (1 votes)
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