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a!+ b!+ c!= abc a (Posted on 2011-08-14) Difficulty: 2 of 5
Determine all possible triplet(s) (a, b, c) satisfying the equation given below where each of the small letters in bold represents a base-11 digit from 0 to A (whether same or different) and a is nonzero.(No computer programs.)

a!+ b!+ c!= abc a

Note: abc represents the concatenation of the three digits.

No Solution Yet Submitted by K Sengupta    
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  Subject Author Date
Some ThoughtsOne tripletJer2011-08-21 01:35:05
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