All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Just Math
a!+ b!+ c!= abc a (Posted on 2011-08-14) Difficulty: 2 of 5
Determine all possible triplet(s) (a, b, c) satisfying the equation given below where each of the small letters in bold represents a base-11 digit from 0 to A (whether same or different) and a is nonzero.(No computer programs.)

a!+ b!+ c!= abc a

Note: abc represents the concatenation of the three digits.

No Solution Yet Submitted by K Sengupta    
No Rating

Comments: ( You must be logged in to post comments.)
  Subject Author Date
Some ThoughtsOne tripletJer2011-08-21 01:35:05
Please log in:
Remember me:
Sign up! | Forgot password

Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (1)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Copyright © 2002 - 2021 by Animus Pactum Consulting. All rights reserved. Privacy Information