Note that 26x26 divided by 3x5 gives 1 remainder, so it's worth asking, is there a configuration that leaves this 1 remainder?
In fact there is. If you cover the top left area with a 20x21 rectangle, the top right with a 21x5 rectangle, the bottom right with a 5x6 rectangle, and the bottom left with a 6x20 rectangle, there will be one square missing. Thus, simply covering that square with an extra piece will finish the covering.
(Edit: now the area is covered with "rectangles")
Edited on June 25, 2011, 2:35 pm
Posted by Gamer
on 2011-06-25 01:45:40