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Going Maximum With Perfect Cubes (Posted on 2011-10-15) Difficulty: 3 of 5
Determine the maximum possible value of a positive base 10 perfect cube M, such that we will obtain another perfect cube by deleting the last three digits of M.

Note: M cannot contain any leading zeroes and each of the last three digits of M is nonzero.

No Solution Yet Submitted by K Sengupta    
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Solution Possible solution Comment 1 of 1
Since y is less than 1000, the only solutions are {a,b,y}={1,11,331}{1,12,728}
So M=1728=12^3
  Posted by broll on 2011-10-15 11:02:11
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