All about
flooble

fun stuff

Get a free chatterbox

Free JavaScript

Avatars
perplexus
dot
info
Home
>
Just Math
Some Squares Sum Square (
Posted on 20120730
)
Determine all possible
non zero real triplet(s)
(F, G, H)
that satisfy the following system of equations:
(7F)
^{2}
+ (7G)
^{2}
+ (7H)
^{2}
= (2F + 3G + 6H)
^{2}
, and :
1/F + 1/G + 1/H = 1
No Solution Yet
Submitted by
K Sengupta
No Rating
Comments: (
Back to comment list
 You must be logged in to post comments.
)
Hint
 Comment 3 of 9 
There is a very elementary (D2) method for determining the triplet(s) and proving that no further triplets exist.
The method basically involves rearranging the terms in the first equation and due substitution into the second equation.
It is important in this connection to remember that none of F, G and H can be imaginary numbers.
Edited on
July 31, 2012, 2:04 pm
Posted by
K Sengupta
on 20120731 05:18:05
Please log in:
Login:
Password:
Remember me:
Sign up!

Forgot password
Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ

About This Site
Site Statistics
New Comments (4)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On
Chatterbox:
blackjack
flooble's webmaster puzzle
Copyright © 2002  2017 by
Animus Pactum Consulting
. All rights reserved.
Privacy Information