A friend presented an easy puzzle to me:
"Given the digits 2 3 4 5 6 , insert 4 mathematical operators between them, do not change the order and get 10 as a result."
My solution was (2^3+4)*5/6 to which my friend reacted by:
"Exponentiation is not permitted, use just the 4 arithmetical operations (or less) and not more than one pair of brackets."

I've found a solution and dare you to find it or maybe find other solutions as well.

• (2 + 3 + 4 - 5 + 6)= 10
• (2 + 3)* 4 / 5 + 6 = 10
• (2 / 3 - 4 + 5)* 6 = 10
•  2 *(3 + 4 - 5)+ 6 = 10
•  2 * 3 - 4 *(5 - 6)= 10
•  2 * 3 - 4 /(5 - 6)= 10
•  2 / 3 *(4 + 5 + 6)= 10

In the first expression, the parentheses are not needed. They also may group any of the operations or group of operations in the expression as they are at the same level of priority.

Edited on January 6, 2013, 6:43 am

Posted by Dej Mar on 2012-12-28 17:43:15