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 Just arithmetic signs (Posted on 2012-12-28)
A friend presented an easy puzzle to me:
"Given the digits 2 3 4 5 6 , insert 4 mathematical operators between them, do not change the order and get 10 as a result."
My solution was (2^3+4)*5/6 to which my friend reacted by:
"Exponentiation is not permitted, use just the 4 arithmetical operations (or less) and not more than one pair of brackets."

I've found a solution and dare you to find it or maybe find other solutions as well.

 Submitted by Ady TZIDON Rating: 2.3333 (3 votes) Solution: (Hide) 2 + 3 + 4 - 5 + 6 = 10 (2 + 3)* 4 / 5 + 6 = 10 (2 / 3- 4 + 5)* 6 = 10 2 *(3 + 4 - 5)+ 6 = 10 2 * 3 - 4 *(5 - 6)= 10 2 * 3 - 4 /(5 - 6)= 10 2 / 3 *(4 + 5 + 6)= 10 (compiled by Dej Mar)

 Subject Author Date re: More solutions W E L C O M E Ady TZIDON 2013-01-06 10:04:49 More solutions Dej Mar 2013-01-06 07:36:10 re(3): How about .. 2 questions & 1 remark. Ady TZIDON 2013-01-05 17:34:10 re(2): How about .. 2 questions & 1 remark. Charlie 2013-01-05 08:36:24 re: How about .. 2 questions & 1 remark. Ady TZIDON 2013-01-05 04:52:23 re: solutions .....2 MINOR ERRORS: Ady TZIDON 2013-01-05 04:45:39 re: solutions brianjn 2012-12-28 20:15:05 solutions Dej Mar 2012-12-28 17:43:15 A solution (didn't look at Charlie's) Kenny M 2012-12-28 11:13:50 How about ... Charlie 2012-12-28 10:50:34

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