All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars
 perplexus dot info

 Tower Travail (Posted on 2013-05-10)
```
+---+                         +---+
| 9 |→ 9                      |   |→ 9
+---+                         +---+
| 8 |→ 8                      |   |→ 8
+---+                         +---+
| 1 |→ 7                      |   |→ 7
+---+                         +---+
| 0 |→ 6                      |   |→ 6
+---+                         +---+
| 5 |→ 5                      |   |→ 5
+---+                         +---+
| 4 |→ 4                      |   |→ 4
+---+                         +---+
↑     | 3 |→ 3                ↑     |   |→ 3
+---+---+ +---+               +---+---+ +---+
| 7 | 2 | | 6 |→ 2            |   |   | |   |→ 2
+---+---+ +---+               +---+---+ +---+```
As the elevator rises along the eight-floor tower, it forms a series of three- digit numbers by combining the 72 in the elevator with the digit on the floor.

What's more, these three-digit numbers are multiples of 2, 3, 4, etc., up to 9. (That is, on the lowest floor, 726 is evenly divisible by 2, on the next floor, 723 is evenly divisible by 3, and so on.)

Find another arrangement for the digits 0 to 9 (using each digit exactly once, one digit per box) so that the elevator isn't 72 and the combinations of the elevator with the level form an appropriate multiple.

 No Solution Yet Submitted by K Sengupta No Rating

Comments: ( Back to comment list | You must be logged in to post comments.)
 Different Listing Comment 2 of 2 |
The following listing yields the same results as found by Charlie:
OPEN "C:\QB64\WORK\ELEVATOR.txt" FOR OUTPUT AS #1

FOR a = 0 TO 9
IF used(a) = 0 THEN
used(a) = 1
FOR b = 0 TO 9
IF used(b) = 0 THEN
used(b) = 1
FOR c = 0 TO 9
IF used(c) = 0 THEN
used(c) = 1
FOR d = 0 TO 9
IF used(d) = 0 THEN
used(d) = 1
FOR e = 0 TO 9
IF used(e) = 0 THEN
used(e) = 1
FOR f = 0 TO 9
IF used(f) = 0 THEN
used(f) = 1
FOR g = 0 TO 9
IF used(g) = 0 THEN
used(g) = 1
FOR h = 0 TO 9
IF used(h) = 0 THEN
used(h) = 1
FOR i = 0 TO 9
IF used(i) = 0 THEN
used(i) = 1
FOR j = 1 TO 9
IF used(j) = 0 THEN
used(j) = 1
sc = 0
s = j * 100 + i * 10 + a
t = j * 100 + i * 10 + b
u = j * 100 + i * 10 + c
v = j * 100 + i * 10 + d
w = j * 100 + i * 10 + e
x = j * 100 + i * 10 + f
y = j * 100 + i * 10 + g
z = j * 100 + i * 10 + h
IF s / 9 = INT(s / 9) THEN sc = sc + 1
IF t / 8 = INT(t / 8) THEN sc = sc + 1
IF u / 7 = INT(u / 7) THEN sc = sc + 1
IF v / 6 = INT(v / 6) THEN sc = sc + 1
IF w / 5 = INT(w / 5) THEN sc = sc + 1
IF x / 4 = INT(x / 4) THEN sc = sc + 1
IF y / 3 = INT(y / 3) THEN sc = sc + 1
IF z / 2 = INT(z / 2) THEN sc = sc + 1
IF sc = 8 THEN
PRINT j * 100 + i * 10; a; b; c; d; e; f; g; h
PRINT #1, j * 100 + i * 10; a; b; c; d; e; f; g; h
END IF

used(j) = 0
END IF
NEXT
used(i) = 0
END IF
NEXT
used(h) = 0
END IF
NEXT
used(g) = 0
END IF
NEXT
used(f) = 0
END IF
NEXT
used(e) = 0
END IF
NEXT
used(d) = 0
END IF
NEXT
used(c) = 0
END IF
NEXT
used(b) = 0
END IF
NEXT
used(a) = 0
END IF
NEXT

CLOSE 1

Finds:
530  1  6  9  4  0  2  7  8
720  9  0  1  6  5  4  3  8
720  9  0  1  6  5  8  3  4
720  9  8  1  0  5  4  3  6
720  9  8  1  6  5  0  3  4
720  9  8  1  6  5  4  3  0

Note that the 3 digit numerals in the left column are the values of the elevator. The numbers in bold, at the right, are to be added to the elevator value.  538 is the only value not preceded by "72".

 Posted by brianjn on 2013-05-10 19:22:14

 Search: Search body:
Forums (0)