Find all values of b such that the equation
bx = logbx
has exactly one real solution.
(In reply to possible solution
When b is below a certain value, found around b=.06, there seems to be two real solutions rather than one.
The trick is to find where exactly, near .06 that it changes from two solutions below that value to one solution between there and 1.
Posted by Charlie
on 2012-12-12 17:24:19