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Twins I (Posted on 2013-01-20) Difficulty: 3 of 5

Let N, a number greater than 5, be the smaller member of a twin prime pair (e.g. {11,13} {17,19} etc.)

It is easily shown that if m=6 then N mod(m) = 5 - though, of course, 5 is itself the smaller member of a twin prime pair.

More interestingly:
(a) for what other values of m is every possible value of N mod(m) also the smaller member of a twin prime pair?
(b) Explain the phenomenon.

No Solution Yet Submitted by broll    
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  Subject Author Date
Hints/TipsExamplesbroll2013-01-22 07:41:59
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