Determine all possible pairs (x,y) of
halfintegers, with x ≤ y, that satisfy this equation:
[x
^{2}] + [y
^{2}] = 2016
Prove that there are no others.
*** [x] denotes the greatest integer ≤ x.
(In reply to
computer solution by Charlie)
Charlie:
WolframAlpha: floor[((2a1)/2)^2] + floor[((2b1)/2)^2]=2016, x=2a1, y=2b1 gives {x,y} = {±85,±29}{±71,±55}{±55,±71}{±29,±85} for a total of 16 solutions.
Edited on August 1, 2013, 3:14 am

Posted by broll
on 20130801 03:11:55 