All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Just Math
Quadratic Quandary (Posted on 2013-11-04) Difficulty: 3 of 5
g(x) is a quadratic function given by:
g(x) = x2 + 12x + 30.

Determine all possible real roots of this equation:
g(g(g(g(g(x))))) = 0

No Solution Yet Submitted by K Sengupta    
No Rating

Comments: ( Back to comment list | You must be logged in to post comments.)
Solution approximate | Comment 1 of 6
A graph of g(x) is a parabola with a minimum at (-6,-6)
A graph of g(x) - c is a parabola with a minimum at (-6,-6-c)
The interesting thing about this is g(x)-c  has two roots, one less than -6 and the other greater than -6.  But if c is less than -6 the roots are imaginary.
So if we work backwards we only need the + of the ħin the quadratic formula.
So here is what I did on my calculator:
0 [enter]
0
(-12+√(12²-4(30-[ans]))/2 [enter]
-3.550510257
-4.43491542
-4.748966595
-4.881503954
-4.942410266





  Posted by Jer on 2013-11-04 15:43:48
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (4)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2017 by Animus Pactum Consulting. All rights reserved. Privacy Information