Determine the respective last digit and the first digit (reading left to right) in the base ten expansion of
23^{232323}
Remember that this is evaluated starting at the topright and proceeding down and to the left.
(In reply to
computeraided solution to part 1 by Charlie)
23^(23^23) itself is a 28433514504467493128360275814989digit number. So even if we took log(23) and multiplied by this huge number (presumably by taking log(log(23)) and adding log(23^(23^23)) ), we'd still be in trouble taking antilog (raising 10 to the power) twice. If we only had to do it once, we could get the first few digits by truncating the integer part. But since the result has to be used again to take the antilog again, we can't truncate that integer part of the original logarithm.

Posted by Charlie
on 20131115 12:24:35 