All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Just Math
Proof (Posted on 2002-05-29) Difficulty: 3 of 5
Prove that 3.999... = 4

See The Solution Submitted by Half-Mad    
Rating: 3.6667 (9 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
re: Then... | Comment 3 of 45 |
(In reply to Then... by Dulanjana)

Yes, but not as a different number from 4. Between any two numbers it is possible to find "at least one" (actually an infinite number) of intermediate numbers. But with 3.999..., if you were to add o.ooo... 00100... (with the 1 in any space but the "last" space), the resulting number would be greater than 4, not between 3.9999.... and 4

On the other hand, 3.999... is useful as an alternate way of writing 4, and similar notation for other whole numbers makes sense of the following sum: 1/3 + 2/3 = .3333... + .6666... = .9999...
  Posted by TomM on 2002-06-08 12:36:07

Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (24)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information