All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Numbers
LCM equation (Posted on 2013-11-19) Difficulty: 2 of 5
The least common multiple (LCM) of 2 numbers is the smallest number that they both divide evenly into.
e.g.:
LCM(8,10)=40
LCM(17,11)=187

For any integer n, show that LCM(9n + 8, 6n + 5) = 54n^2 + 93n + 40.

No Solution Yet Submitted by Ady TZIDON    
Rating: 4.3333 (3 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Solution Puzzle Solution Comment 6 of 6 |
We observe that for integers 2 and -3, 
2(9n+8)+(-3)(6n+5)=1
Therefore, in terms of Bezout's Lemma,  we must have:
gcd(9n+8, 6n+5) = 1

We know that:
                       a*b
lcm(a,b) = ---------------
                    gcd(a,b)

Then, lcm(9n+8, 6n+5) 
= (9n+8)(6n+5),  since gcd(9n+8,6n+5) = 1
= 54n^2 + 45n+48n+40
= 54n^2 +93n+40

Edited on May 21, 2022, 10:18 am
  Posted by K Sengupta on 2022-05-18 23:53:29

Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (12)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information