You could add the symbol 0 as an exponent three times. Pretend the degree sign is a zero: 3º*5º=6º
You could also write three 0's to the lower left of the numerals to make them appear as exponents:
0^3*0^5=0^6
Or use 1's
1^3*1^5=1^6
If you allow the differential operator d/dx as a single symbol you get
d3/dx*d5/dx=d6/dx
which is true because 0*0=0
If you use the prime notation for a derivative this is the same as
3'*5'=6'
Is this is a 'word problem'?
I can't think of solutions for
THREE TIMES FIVE EQUALS SIX

Posted by Jer
on 20140108 11:32:52 