Solve:

E E O
+ E O O
---------
O E O E

Given that:

- The above alphanumeric equation uses each of the digits from 0 to 9 exactly once.
- O denotes an odd digit and E denotes an even digit. Zero is considered as an even digit.
- Each digit in the top row is greater than the digit immediately below it.

(In reply to

re: corrected and solved by xdog)

You claim: "Solutions are 423+675, 425+673, 623+475, 625+473, all summing to 1098 .

**None of the above fulfills the condition 3: digit 2 is above 7 and 2<7.**

With no constraints there would exist 2^3=8 solutions.