All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Numbers
A partial deck (Posted on 2014-03-05) Difficulty: 2 of 5
From a full 52-card deck of playing cards some cards were removed.
Now we shuffle and draw 2 cards and find them both red.

1. The probability of both cards being red was 50%.
2. There was an equal number of cards in each of the following suits: CLUBS, DIAMONDS & SPADES.

How many hearts were initially in the partial deck?

No Solution Yet Submitted by Ady TZIDON    
No Rating

Comments: ( Back to comment list | You must be logged in to post comments.)
Hints/Tips re: Solution ....... att: Jer | Comment 2 of 3 |
(In reply to Solution by Jer)


(3,3,12,3) is a correct answer for set (C,D,H,S).

however in

Probability of red  ...2nd draw = (x+h-1)/(3x+h)


(Probability of red  ...2nd draw = (x+h-1)/(3x+h-1).

Please edit.

BTW -you still did not comment on my last remark re "penta-quadratic"

  Posted by Ady TZIDON on 2014-03-05 10:56:39
Please log in:
Remember me:
Sign up! | Forgot password

Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (8)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Copyright © 2002 - 2019 by Animus Pactum Consulting. All rights reserved. Privacy Information