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A partial deck (Posted on 2014-03-05) Difficulty: 2 of 5
From a full 52-card deck of playing cards some cards were removed.
Now we shuffle and draw 2 cards and find them both red.

Given:
1. The probability of both cards being red was 50%.
2. There was an equal number of cards in each of the following suits: CLUBS, DIAMONDS & SPADES.

How many hearts were initially in the partial deck?

No Solution Yet Submitted by Ady TZIDON    
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Hints/Tips re: Solution ....... att: Jer | Comment 2 of 3 |
(In reply to Solution by Jer)

 

(3,3,12,3) is a correct answer for set (C,D,H,S).

however in

Probability of red  ...2nd draw = (x+h-1)/(3x+h)

s.b:

(Probability of red  ...2nd draw = (x+h-1)/(3x+h-1).

Please edit.

BTW -you still did not comment on my last remark re "penta-quadratic"



  Posted by Ady TZIDON on 2014-03-05 10:56:39
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