The equation x^xy^y=z^z has trivial integer solutions if x=1 or y=1. What is the smallest solution to x^xy^y=z^z where x, y, and z are integers and 1<x≤y?

(In reply to solution by xdog)

{a=b=1}, (az)^a + (bz)^b = 2z, not z.

Edited on July 14, 2014, 1:57 am

Posted by broll on 2014-07-14 01:09:15