BC, CA and AB represents three sides of a triangle having lengths a, b and c respectively. Angles A, B and C are opposite respectively to the sides BC, CA and AB
Given that: a
^{2} + b
^{2}= 2015* c
^{2}
Find the value of :
cot C

cot A + cot B
The answer seems to be around 2014/2.
By direct evaluation:
Let c=1, and a=b (a very pointy isosceles triangle)
Then a=b=31.7411409...
The angle at C is 1.80516983... degrees, that at A and B is (901.80516983.../2)
Computation gives the value of the desired expression as 1007.000..
Edited on October 20, 2014, 12:15 am

Posted by broll
on 20141019 23:59:45 