perplexus.info :: Just Math : Divisible by 28

Divisible by 28 (Posted on 2014-12-21)

Each of a, b and c is a positive integer with a ≤ b ≤ c ≤ 70.

Find total number of triplets (a, b, c) such that a² + b² + c² is divisible by 28.

See The Solution Submitted by K Sengupta

Rating: 5.0000 (1 votes)

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re(2): possible solution.....TNX

Comment 4 of 4 |

(In reply to re: possible solution by Dej Mar)

Thanks you, Dej Mar, for pointing out my error.

Please read my corrected version, I added explanation how the sets were compiled.

Posted by Ady TZIDON on 2014-12-21 23:46:36

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