Yes.

Alternatively: x(2-x)-1 =z^2; -(x-1)^2 = z^2, and z has to be 0, so x is 1. y+1=2 simplifies to y=1.

So x^{5} + y^{5} + z^{5}= 2.

Edited on February 1, 2015, 11:34 pm

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