At x=0 the LHS is 0.
At x=1 the LHS is 0.
At x = 2 the LHS is -2.
Therefore 0 <= m < 2, as m=2 results in only one solution.
For negative m, one of the solutions will be negative. Above 2 and there will be no real solutions.
Corrected value of LHS for x=2, per Jer's comment.
Edited on February 5, 2015, 3:24 pm
Posted by Charlie
on 2015-02-04 15:25:24