All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Just Math
Simultaneous Pythagorean Poser 2 (Posted on 2015-09-05) Difficulty: 3 of 5
Find all possible triplets (A, B, C) of positive integers, with A ≤ B, that satisfy this system of equations:

A2 + B2 = C2, and

A+B = 2C - 99

No Solution Yet Submitted by K Sengupta    
No Rating

Comments: ( Back to comment list | You must be logged in to post comments.)
Solution corrected computer solution Comment 4 of 4 |
(In reply to Solution, with thanks to the classical Greeks by xdog)

  a   b      c
 15 112   113
 27 120   123
 55 132   143
 72 135   153
 84 135   159
 99 132   165
119 120   169

Two more solutions appear than in xdog's solution: the first and the last.

DefDbl A-Z

Dim crlf$

Private Sub Form_Load()

 Form1.Visible = True

 

 Text1.Text = ""

 crlf = Chr$(13) + Chr$(10)


 For tot = 2 To 50000

  For a = 1 To tot / 2

   b = tot - a

   c = (a + b + 99) / 2

   If c = Int(c) And a * a + b * b = c * c Then

       Text1.Text = Text1.Text & a & Str(b) & "   " & c & crlf

       DoEvents

   End If

  Next

 Next

 

 

 Text1.Text = Text1.Text & crlf & " done"

  

End Sub





  Posted by Charlie on 2015-09-06 08:46:20
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (4)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2017 by Animus Pactum Consulting. All rights reserved. Privacy Information