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Consider the definition of a log, and you will see that loga(b) = 1/(logb(a)).
Let's say that logy(x) equals some number A. Then A + 1/A = 43. This can be written in the form: A^2 + 1 = 43A.
Solving this quadratic equation yields A = 43.977 or A = 0.023. (These two values are reciprocal of one another, so they are identical for our purposes)
Now to solve the problem, take any number (such as 2) and raise it to the power of 42.977. As you can see, there is an infinite number of solutions, but none of them are particularly elegant. |
