(In reply to
re(2): possible solution. //infinitely many ? by broll)
let A=a(a+1)/2 and B=b^2 then we need
a(a+1)/2b^2=2015
a^2+a2b^2=4030
now using:
http://www.alpertron.com.ar/QUAD.HTM
we get the following generic solution
for any solution a,b we have another solution x,y
x=3a+4b+1
y=2a+3b+1
Thus there are indeed an infinite number of solutions

Posted by Daniel
on 20151014 07:11:46 