A number of 50 digits has all its digits equal to 1 except the 26th digit. If the number is divisible by 13, then find the digit in the 26th place.
(Responding to Ady TZIDON)
That's a nifty approach, but don't we count digits beginning at the decimal? If so, you still might get a variant of your method to work.
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Posted by NK
on 2004-02-10 18:13:08 |