perplexus.info :: Just Math : 50

50 - Digit Number (Posted on 2003-11-15)

A number of 50 digits has all its digits equal to 1 except the 26th digit. If the number is divisible by 13, then find the digit in the 26th place.

See The Solution Submitted by Ravi Raja

Rating: 3.0000 (7 votes)

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Subject	Author	Date
School Education	Christopher Jaeger	2022-04-16 11:25:12
Explanation for Puzzle Answer	K Sengupta	2022-01-31 21:06:48
Puzzle Answer	K Sengupta	2022-01-31 20:49:32
re: A similar problem but perhaps a bit trickier	hepev92013	2020-09-29 12:22:49
answer	K Sengupta	2008-03-20 09:46:36
Solution	Praneeth	2007-09-11 08:20:38
re(2): Re so easy SECOND OPINION att :NK	Ady TZIDON	2004-02-11 07:24:20
re: Re so easy	NK	2004-02-10 19:03:12
Re so easy	NK	2004-02-10 18:13:08
so easy	Ady TZIDON	2004-02-10 15:08:55
Correction to Another Approach	NK	2004-02-10 11:21:08
Another Approach	NK	2004-02-10 10:32:01
re: Digit number	Richard	2004-01-24 17:51:29
Digit number	Purna	2004-01-24 06:17:38
re: solution	Richard	2003-12-31 13:22:37
solution	luminita	2003-12-31 11:27:06
re(7): solution	Richard	2003-11-23 12:24:27
re(6): solution	SilverKnight	2003-11-23 02:11:44
re(5): solution	Richard	2003-11-22 21:34:28
No Subject	Richard	2003-11-22 21:31:34
re(4): solution	Kirk	2003-11-22 18:49:19
re: correction	Kirk	2003-11-22 18:39:12
correction	Richard	2003-11-22 12:54:55
re(3): solution	Richard	2003-11-21 17:48:09
re(2): solution	Kirk	2003-11-21 16:33:21
re: solution	Richard	2003-11-20 20:35:49
re(6): a little more straightforward	Tristan	2003-11-20 19:31:37
re: A similar problem but perhaps a bit trickier	Richard	2003-11-20 17:47:15
re(3): A similar problem but perhaps a bit trickier	Kirk	2003-11-20 17:17:18
re(2): A similar problem but perhaps a bit trickier	Kirk	2003-11-20 17:13:45
re: A similar problem but perhaps a bit trickier	Charlie	2003-11-20 14:59:49
A similar problem but perhaps a bit trickier	Kirk	2003-11-20 14:53:01
re(5): a little more straightforward	Richard	2003-11-19 21:30:45
re(4): a little more straightforward	Richard	2003-11-19 21:21:06
re(3): a little more straightforward	Tristan	2003-11-19 19:06:25
re(2): a little more straightforward	Richard	2003-11-19 01:59:52
re: a little more straightforward	Richard	2003-11-19 00:10:42
re: a little more straightforward	Tristan	2003-11-16 20:52:59
re: a little more straightforward	Victor Zapana	2003-11-16 12:57:06
a little more straightforward	Eric	2003-11-16 01:07:26
Less thinking using extended precision	Charlie	2003-11-15 11:46:40
solution	Charlie	2003-11-15 11:32:16
first thoughts	rerun141	2003-11-15 11:06:34

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