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 50 - Digit Number (Posted on 2003-11-15)
A number of 50 digits has all its digits equal to 1 except the 26th digit. If the number is divisible by 13, then find the digit in the 26th place.

 See The Solution Submitted by Ravi Raja Rating: 3.3333 (6 votes)

 Subject Author Date answer K Sengupta 2008-03-20 09:46:36 Solution Praneeth 2007-09-11 08:20:38 re(2): Re so easy SECOND OPINION att :NK Ady TZIDON 2004-02-11 07:24:20 re: Re so easy NK 2004-02-10 19:03:12 Re so easy NK 2004-02-10 18:13:08 so easy Ady TZIDON 2004-02-10 15:08:55 Correction to Another Approach NK 2004-02-10 11:21:08 Another Approach NK 2004-02-10 10:32:01 re: Digit number Richard 2004-01-24 17:51:29 Digit number Purna 2004-01-24 06:17:38 re: solution Richard 2003-12-31 13:22:37 solution luminita 2003-12-31 11:27:06 re(7): solution Richard 2003-11-23 12:24:27 re(6): solution SilverKnight 2003-11-23 02:11:44 re(5): solution Richard 2003-11-22 21:34:28 No Subject Richard 2003-11-22 21:31:34 re(4): solution Kirk 2003-11-22 18:49:19 re: correction Kirk 2003-11-22 18:39:12 correction Richard 2003-11-22 12:54:55 re(3): solution Richard 2003-11-21 17:48:09 re(2): solution Kirk 2003-11-21 16:33:21 re: solution Richard 2003-11-20 20:35:49 re(6): a little more straightforward Tristan 2003-11-20 19:31:37 re: A similar problem but perhaps a bit trickier Richard 2003-11-20 17:47:15 re(3): A similar problem but perhaps a bit trickier Kirk 2003-11-20 17:17:18 re(2): A similar problem but perhaps a bit trickier Kirk 2003-11-20 17:13:45 re: A similar problem but perhaps a bit trickier Charlie 2003-11-20 14:59:49 A similar problem but perhaps a bit trickier Kirk 2003-11-20 14:53:01 re(5): a little more straightforward Richard 2003-11-19 21:30:45 re(4): a little more straightforward Richard 2003-11-19 21:21:06 re(3): a little more straightforward Tristan 2003-11-19 19:06:25 re(2): a little more straightforward Richard 2003-11-19 01:59:52 re: a little more straightforward Richard 2003-11-19 00:10:42 re: a little more straightforward Tristan 2003-11-16 20:52:59 re: a little more straightforward Victor Zapana 2003-11-16 12:57:06 a little more straightforward Eric 2003-11-16 01:07:26 Less thinking using extended precision Charlie 2003-11-15 11:46:40 solution Charlie 2003-11-15 11:32:16 first thoughts rerun141 2003-11-15 11:06:34

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