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trigonometry and a triangle (Posted on 2004-02-26) |
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Prove that in a triangle ABC,:
sin(A)sin(B)sin(C) + cos(A)cos(B) = 1
implies:
A = B = 45° and C = 90°.
re: solution
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| Comment 5 of 15 |
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(In reply to solution by jacob)
Very nice.
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