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Special Numbers (Posted on 2004-04-03) Difficulty: 2 of 5
There exists a number oddity with 3 different 4-digit numbers. One is 9801, where (98 + 01)^2 = 9801. It also works with 3025: (30+25)^2 = 3025.
What is the other number?
What is the smallest 6-digit number that would work?
(in other words, in a 6-digit number abcdef: abcdef=(abc+def)^2)

See The Solution Submitted by Victor Zapana    
Rating: 3.6667 (6 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Algebraic Setup | Comment 7 of 19 |
Because 01=1, from a uniqueness perspective I conclude it is best to approach this by using two two digit numbers and call them (x,y) and because we know x>9 (must be four digit numbers) ask for what values of x>9 and y other then (30,25) and (98,01) does (x+y)²=y+100*x hold?  Not sure how to approach this however.
  Posted by Mike on 2004-04-04 15:46:25
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