Given a clock, rearrange six consecutive numbers on its face, so
the sum of every pair of adjacent numbers is a prime.
My other post was half of the solution, i just had to rearrange the other six numbers!!
Now the solution: 11 12 1 2 3 4 7 10 9 8 5 6
|
Posted by Isabel
on 2004-08-02 04:17:34 |