The equation a!b!=c! is trivial if we allow a or b to be 0 or 1.

However, adding that 1<a<b<c, also allows trivial solutions: which? What condition should be added to disallow such solutions?

Finally, adding that condition, can you find any solution to the problem?

b=a!-1 does it

e.g. a=4 b=23 c= 4!*23!=24!

infinite number of solutions

ady

Posted by Ady TZIDON on 2004-08-16 10:30:42