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Factorials everywhere (Posted on 2004-08-16) Difficulty: 3 of 5
The equation a!b!=c! is trivial if we allow a or b to be 0 or 1.

However, adding that 1<a<b<c, also allows trivial solutions: which? What condition should be added to disallow such solutions?

Finally, adding that condition, can you find any solution to the problem?

See The Solution Submitted by Federico Kereki    
Rating: 2.6000 (5 votes)

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More trivial solutions | Comment 3 of 6 |


As pointed out, b=a!-1 is a family of trivial solutions. More generally, (b+1)(b+2)...=a! is a family of solutions. If these solutions are also elimited, another solution gets harder, still working on that one.

  Posted by Rajal on 2004-08-16 11:17:58
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