Three cubes of volume 1, 8, and 64 are glued together.
What is the smallest possible surface area of the resulting configuration?
-Problem taken from UNL Math Day
(In reply to
re: As easy as 1,2,4 (corrections) by np_rt)
DOH!
I can do the long algebraic equations, but it's always the simple things that trip me up. (You mean 2 +2 is not 5?)
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Posted by TomM
on 2002-12-25 02:52:21 |