Four chords of a circle are arranged in such a way that they form a quadrilateral shape, the length of the chords are as follows.

6cm, 7cm, 8cm and 9cm.

what is the area of the circle that will intersect all of the points?

(In reply to Solution (some cheating) by Jer)

I don't have a proof yet, but I get that R = 5.363825 so the area is 90.385564.

But at the same time I usually thoroughly confuse myself in these problems.  Your R is almost half of mine.  I wonder if I got confused between a diameter and a radius.  Argh.

More to come, I think.

Posted by nikki on 2005-01-11 21:08:10