perplexus.info :: Just Math : Chord Harmonics

Chord Harmonics (Posted on 2005-01-11)

Four chords of a circle are arranged in such a way that they form a quadrilateral shape, the length of the chords are as follows.

6cm, 7cm, 8cm and 9cm.

what is the area of the circle that will intersect all of the points?

No Solution Yet Submitted by Juggler

Rating: 4.0000 (3 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)

solution: re(2): Solution (some cheating)

| Comment 3 of 9 |

(In reply to re: Solution (some cheating) by nikki)

I too got a radius of 5.364, which would yield 90.379 which I believe is close to what nikki derived, somewhere one of us lost some significant digits in rounding (probably mine)

Posted by Christian on 2005-01-12 03:12:46

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